C-10-Q081mediumsingle_mcq

Numerically $x$ equals—

a $10\sqrt{3}$ m
b $\dfrac{10}{\sqrt{3}}$ m
c $\dfrac{\sqrt{3}}{10}$ m
d $30$ m

ব্যাখ্যা

Since $\tan 30^\circ = \frac{1}{\sqrt{3}}$ , we get $x = \frac{10}{1/\sqrt{3}} = 10\sqrt{3}$ . This is the height of the still-standing portion of the pole.

এই অধ্যায়ের আরও প্রশ্ন

C-10-Q082From the same triangle, equals—
C-10-Q083So the broken piece equals—
C-10-Q084The total height of the pole is approximately—
C-10-Q085The unbroken (still standing) piece measures approximately—
C-10-Q086The slanted (broken) piece measures exactly—
C-10-Q087A balloon flies above a point between two posts km apart on level ground. From the balloon, the depression of
C-10-Q088The horizontal distance to the foot of the post equals—
C-10-Q089The two horizontal distances together equal the spacing between the posts—
C-10-Q090Solving gives
C-10-Q091Approximate height of the balloon above the ground in metres—

Chapter 10: Distance and Elevation — সব প্রশ্ন দেখুন (160টি) →

Numerically $x$ equals—

10\sqrt{3}

\dfrac{10}{\sqrt{3}}

\dfrac{\sqrt{3}}{10}

30

ব্যাখ্যা

Since $\tan 30^\circ = \frac{1}{\sqrt{3}}$ , we get $x = \frac{10}{1/\sqrt{3}} = 10\sqrt{3}$ . This is the height of the still-standing portion of the pole.

Numerically xxx equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Numerically xxx equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Numerically $x$ equals—

Numerically $x$ equals—