C-10-Q066mediumsingle_mcq

From right $\triangle ABC$ with stick $BC$ as hypotenuse, $\sin \angle ACB$ equals—

a $\dfrac{AB}{BC}$
b $\dfrac{BC}{AB}$
c $\dfrac{AB}{AC}$
d $\dfrac{AC}{AB}$

ব্যাখ্যা

Sine of the angle equals the opposite side over the hypotenuse. Here $AB$ is opposite $\angle ACB$ and the stick $BC$ is the hypotenuse, so $\sin\angle ACB=\dfrac{AB}{BC}$ .

এই অধ্যায়ের আরও প্রশ্ন

C-10-Q067Therefore equals—
C-10-Q068The length of the stick in Example 4 is—
C-10-Q069The reasoning that the depression angle at equals at uses the fact that the two horizontal lines at and at are
C-10-Q070Angle of depression from a higher point and angle of elevation from a lower point form—
C-10-Q071Building height , , with . Then equals—
C-10-Q072From the equation , we get
C-10-Q073Moving back m to point gives elevation , so equals—
C-10-Q074Therefore also equals—
C-10-Q075Combining gives
C-10-Q076Hence approximately equals—

Chapter 10: Distance and Elevation — সব প্রশ্ন দেখুন (160টি) →

From right $\triangle ABC$ with stick $BC$ as hypotenuse, $\sin \angle ACB$ equals—

\dfrac{AB}{BC}

\dfrac{BC}{AB}

\dfrac{AB}{AC}

\dfrac{AC}{AB}

ব্যাখ্যা

Sine of the angle equals the opposite side over the hypotenuse. Here $AB$ is opposite $\angle ACB$ and the stick $BC$ is the hypotenuse, so $\sin\angle ACB=\dfrac{AB}{BC}$ .

From right △ABC\triangle ABC△ABC with stick BCBCBC as hypotenuse, sin⁡∠ACB\sin \angle ACBsin∠ACB equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

From right △ABC\triangle ABC△ABC with stick BCBCBC as hypotenuse, sin⁡∠ACB\sin \angle ACBsin∠ACB equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

From right $\triangle ABC$ with stick $BC$ as hypotenuse, $\sin \angle ACB$ equals—

From right $\triangle ABC$ with stick $BC$ as hypotenuse, $\sin \angle ACB$ equals—