C-10-Q037mediumsingle_mcqtan30∘=?\tan 30^\circ = ?tan30∘=?a3\sqrt{3}3b13\dfrac{1}{\sqrt{3}}31c111d12\dfrac{1}{2}21ব্যাখ্যাtan30∘=sin30∘cos30∘=1/23/2=13\tan 30^\circ = \dfrac{\sin 30^\circ}{\cos 30^\circ} = \dfrac{1/2}{\sqrt{3}/2} = \dfrac{1}{\sqrt{3}}tan30∘=cos30∘sin30∘=3/21/2=31. This is a standard value to memorize.