C-11-Q049mediumsingle_mcq

Componendo: if $a:b = c:d$ , then—

a $\dfrac{a+b}{b} = \dfrac{c+d}{d}$
b $\dfrac{a-b}{b} = \dfrac{c-d}{d}$
c $\dfrac{a}{b+1} = \dfrac{c}{d+1}$
d $a+b = c+d$

ব্যাখ্যা

Componendo adds the consequent to the antecedent over the consequent. Adding $1$ to both sides of $\dfrac{a}{b}=\dfrac{c}{d}$ gives $\dfrac{a+b}{b}=\dfrac{c+d}{d}$ .

এই অধ্যায়ের আরও প্রশ্ন

C-11-Q050Dividendo: if , then—
C-11-Q051Componendo-Dividendo: if , then—
C-11-Q052Componendo is proved by—
C-11-Q053Dividendo is proved by—
C-11-Q054Componendo-Dividendo is obtained by—
C-11-Q055Apply componendo on to get—
C-11-Q056Apply dividendo on to get—
C-11-Q057Apply componendo-dividendo on to get—
C-11-Q058From , the value of is—
C-11-Q059If , then also equals—

Algebraic Ratio and Proportion — সব প্রশ্ন দেখুন (180টি) →

Componendo: if $a:b = c:d$ , then—

\dfrac{a+b}{b} = \dfrac{c+d}{d}

\dfrac{a-b}{b} = \dfrac{c-d}{d}

\dfrac{a}{b+1} = \dfrac{c}{d+1}

a+b = c+d

ব্যাখ্যা

Componendo adds the consequent to the antecedent over the consequent. Adding $1$ to both sides of $\dfrac{a}{b}=\dfrac{c}{d}$ gives $\dfrac{a+b}{b}=\dfrac{c+d}{d}$ .

Componendo: if a:b=c:da:b = c:da:b=c:d, then—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Componendo: if a:b=c:da:b = c:da:b=c:d, then—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Componendo: if $a:b = c:d$ , then—

Componendo: if $a:b = c:d$ , then—