C-11-Q047mediumsingle_mcq

From $a:b = c:d$ , by combining alternendo and invertendo we obtain—

a $b:a = d:c$
b $a:c = b:d$
c $c:a = d:b$
d $a:b = d:c$

ব্যাখ্যা

Alternendo gives $\dfrac{a}{c}=\dfrac{b}{d}$ , and then inverting both sides (invertendo) gives $\dfrac{c}{a}=\dfrac{d}{b}$ , i.e. $c:a=d:b$ . The two operations combine to swap and flip the ratios.

এই অধ্যায়ের আরও প্রশ্ন

C-11-Q048If , then by alternendo
C-11-Q049Componendo: if , then—
C-11-Q050Dividendo: if , then—
C-11-Q051Componendo-Dividendo: if , then—
C-11-Q052Componendo is proved by—
C-11-Q053Dividendo is proved by—
C-11-Q054Componendo-Dividendo is obtained by—
C-11-Q055Apply componendo on to get—
C-11-Q056Apply dividendo on to get—
C-11-Q057Apply componendo-dividendo on to get—

Algebraic Ratio and Proportion — সব প্রশ্ন দেখুন (180টি) →

From $a:b = c:d$ , by combining alternendo and invertendo we obtain—

b:a = d:c

a:c = b:d

c:a = d:b

a:b = d:c

ব্যাখ্যা

Alternendo gives $\dfrac{a}{c}=\dfrac{b}{d}$ , and then inverting both sides (invertendo) gives $\dfrac{c}{a}=\dfrac{d}{b}$ , i.e. $c:a=d:b$ . The two operations combine to swap and flip the ratios.

From a:b=c:da:b = c:da:b=c:d, by combining alternendo and invertendo we obtain—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

From a:b=c:da:b = c:da:b=c:d, by combining alternendo and invertendo we obtain—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

From $a:b = c:d$ , by combining alternendo and invertendo we obtain—

From $a:b = c:d$ , by combining alternendo and invertendo we obtain—