C-03-Q099mediumsingle_mcqIf x−1x=px - \dfrac{1}{x} = px−x1=p, x3−1x3=?x^3 - \dfrac{1}{x^3} = ?x3−x31=?ap3+3pp^3 + 3pp3+3pbp3−3pp^3 - 3pp3−3pcp3p^3p3dpppব্যাখ্যাBy the identity x3−1x3=(x−1x)3+3(x−1x)=p3+3px^3-\dfrac1{x^3}=\left(x-\dfrac1x\right)^3+3\left(x-\dfrac1x\right)=p^3+3px3−x31=(x−x1)3+3(x−x1)=p3+3p.