C-03-Q017mediumsingle_mcqa2+b2=(a+b)2+(a−b)2?a^2 + b^2 = \dfrac{(a+b)^2 + (a-b)^2}{?}a2+b2=?(a+b)2+(a−b)2a111b222c333d444ব্যাখ্যাAdding (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2(a+b)2=a2+2ab+b2 and (a−b)2=a2−2ab+b2(a-b)^2 = a^2 - 2ab + b^2(a−b)2=a2−2ab+b2 gives 2(a2+b2)2(a^2 + b^2)2(a2+b2), so a2+b2=(a+b)2+(a−b)22a^2 + b^2 = \dfrac{(a+b)^2 + (a-b)^2}{2}a2+b2=2(a+b)2+(a−b)2.