C-03-Q019mediumsingle_mcqab=(a+b2)2−?ab = \left(\dfrac{a+b}{2}\right)^2 - ?ab=(2a+b)2−?a(a−b2)2\left(\dfrac{a-b}{2}\right)^2(2a−b)2b(a+b2)2\left(\dfrac{a+b}{2}\right)^2(2a+b)2ca−b2\dfrac{a-b}{2}2a−bdab4\dfrac{ab}{4}4abব্যাখ্যাDividing the identity ab=(a+b)2−(a−b)24ab = \dfrac{(a+b)^2 - (a-b)^2}{4}ab=4(a+b)2−(a−b)2 through by 444 places it in square form, giving ab=(a+b2)2−(a−b2)2ab = \left(\dfrac{a+b}{2}\right)^2 - \left(\dfrac{a-b}{2}\right)^2ab=(2a+b)2−(2a−b)2.