C-12-Q059mediumsingle_mcqABCD is a parallelogram with diagonals AC and BD. AD⃗=\vec{AD}=AD=a12(AC⃗−BD⃗)\frac{1}{2}(\vec{AC}-\vec{BD})21(AC−BD)b12(AC⃗+BD⃗)\frac{1}{2}(\vec{AC}+\vec{BD})21(AC+BD)cAC⃗+BD⃗\vec{AC}+\vec{BD}AC+BDdAC⃗−BD⃗\vec{AC}-\vec{BD}AC−BD