C-12-Q058mediumsingle_mcqABCD is a parallelogram with diagonals AC and BD. AB⃗=\vec{AB}=AB=a12(AC⃗+BD⃗)\frac{1}{2}(\vec{AC}+\vec{BD})21(AC+BD)b12(AC⃗−BD⃗)\frac{1}{2}(\vec{AC}-\vec{BD})21(ACcAC⃗−BD⃗\vec{AC}-\vec{BD}AC−BDdAC⃗+BD⃗\vec{AC}+\vec{BD}AC+BD