C-03-Q127mediumsingle_mcqDe Morgan's theorem states that—ax⋅y‾=x‾+y‾\overline{x \cdot y} = \overline{x} + \overline{y}x⋅y=x+y and x+y‾=x‾⋅y‾\overline{x+y} = \overline{x} \cdot \overline{y}x+y=x⋅ybx+y=y+xx + y = y + xx+y=y+xcx+yz=(x+y)(x+z)x + yz = (x+y)(x+z)x+yz=(x+y)(x+z)dx+x=xx + x = xx+x=x