C-03-Q134mediumsingle_mcqFor the expression x⋅(y+z‾)x \cdot (\overline{y+z})x⋅(y+z), the output is 1 only when—ax=1,y=0,z=0x=1, y=0, z=0x=1,y=0,z=0bx=0,y=1,z=1x=0, y=1, z=1x=0,y=1,z=1cx=1,y=1,z=1x=1, y=1, z=1x=1,y=1,z=1dx=0,y=0,z=0x=0, y=0, z=0x=0,y=0,z=0