C-03-Q134mediumsingle_mcqFor the expression x⋅(y+z‾)x \cdot (\overline{y+z})x⋅(y+z), the output is 1 only when—ax=1,y=0,z=0x=1, y=0, z=0x=1,y=0,z=0bx=0,y=1,z=1