C-03-Q118mediumsingle_mcq
When adding four bits using full adder block diagrams, why is CIN1 = 0 in the first block?
When adding four bits using full adder block diagrams, why is CIN1 = 0 in the first block?
- aThe first block is always disabled
- bNo carry can come from any previous step for the first two bits
- cThe first bit is always 0
- dThe first adder is a half adder