C-01-Q055mediumsingle_mcqA=[abcd]A = \begin{bmatrix} a & b \\ c & d \end{bmatrix}A=[acbd] অব্যতিক্রমী হলে A−1=?A^{-1} = ?A−1=?a1ad−bc[d−b−ca]\dfrac{1}{ad - bc}\begin{bmatrix} d & -b \\ -c & a \end{bmatrix}ad−bc1[d−c−ba]b1ad−bc[abcd]\dfrac{1}{ad - bc}\begin{bmatrix} a & b \\ c & d \end{bmatrix}ad−bc1[acbd]c1ad−bc[a−b−cd]\dfrac{1}{ad - bc}\begin{bmatrix} a & -b \\ -c & d \end{bmatrix}ad−bc1[a−c−bd]d(ad−bc)[d−b−ca](ad - bc)\begin{bmatrix} d & -b \\ -c & a \end{bmatrix}(ad−bc)[d−c−ba]