C-09-Q197mediumsingle_mcqIf cot(θ−30∘)=13\cot(\theta - 30^\circ) = \dfrac{1}{\sqrt{3}}cot(θ−30∘)=31, then sinθ=?\sin\theta = ?sinθ=?a12\dfrac{1}{2}21b32\dfrac{\sqrt{3}}{2}2