C-09-Q190mediumsingle_mcqSolve: tan2θ−(1+3)tanθ+3=0\tan^2\theta - (1 + \sqrt{3})\tan\theta + \sqrt{3} = 0tan2θ−(1+3)tanθ+3=0. θ=?\theta = ?θ=?aonly 45∘45^\circ45∘bonly 60∘60^\circ60∘c or