C-09-Q186mediumsingle_mcqSolve: 2cos2θ+3sinθ−3=02\cos^2\theta + 3\sin\theta - 3 = 02cos2θ+3sinθ−3=0, θ\thetaθ acute. θ=?\theta = ?θ=?a30∘30^\circ30∘b45∘45^\circ45∘c