If $ an A = \dfrac{1}{\sqrt{3}}$, then $\dfrac{\operatorname{cosec}^2 A - \sec^2 A}{\operatorname{cosec}^2 A + \sec^2 A

Question

If $	an A = \dfrac{1}{\sqrt{3}}$, then $\dfrac{\operatorname{cosec}^2 A - \sec^2 A}{\operatorname{cosec}^2 A + \sec^2 A} = ?$

Accepted Answer

$\dfrac{1}{2}$

Answer

$1$

Answer

$-\dfrac{1}{2}$

Answer

$0$

If tan⁡A=13\tan A = \dfrac{1}{\sqrt{3}}tanA=3​1​, then cosec⁡2A−sec⁡2Acosec⁡2A+sec⁡2A=?\dfrac{\operatorname{cosec}^2 A - \sec^2 A}{\operatorname{cosec}^2 A + \sec^2 A} = ?cosec2A+sec2A