C-09-Q095: $\dfrac{\sec A}{\cos A} - \dfrac{\tan A}{\cot A} = ?$

C-09-Q095: $\dfrac{\sec A}{\cos A} - \dfrac{\tan A}{\cot A} = ?$ | প্রশ্ন করি

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sec⁡Acos⁡A−tan⁡Acot⁡A=?\dfrac{\sec A}{\cos A} - \dfrac{\tan A}{\cot A} = ?cosAsecA​−cotAtanA​=?