C-09-Q027mediumsingle_mcqThe relation PMOP=P1M1OP1\dfrac{PM}{OP} = \dfrac{P_1 M_1}{OP_1}OPPM=OP1P1M1 expresses—asimilarity of triangles onlybconstancy of trigonometric ratioscthe Pythagorean theoremda complementary identity