If $C = \{2, 5\}$, $D = \{4, 6, 7\}$, $x \in C$, $y \in D$, the relation $x + 1

Question

If $C = \{2, 5\}$, $D = \{4, 6, 7\}$, $x \in C$, $y \in D$, the relation $x + 1 < y$ gives—

Accepted Answer

$\{(2, 4), (2, 6), (2, 7), (5, 7)\}$

Answer

$\{(2, 4), (2, 6), (2, 7), (5, 6), (5, 7)\}$

Answer

$\{(2, 6), (5, 7)\}$

Answer

$\{(2, 4)\}$

If C={2,5}C = \{2, 5\}C={2,5}, D={4,6,7}D = \{4, 6, 7\}D={4,6,7}, x∈Cx \in Cx∈C, y∈Dy \in Dy∈D, the relation x+1<yx + 1 < yx+1<y gives—