In a parallelogram $ABCD$, a line through $A$ meets $BC$ at $M$ and $DC$ at $N$. Then $BM imes DN = ?$

Question

In a parallelogram $ABCD$, a line through $A$ meets $BC$ at $M$ and $DC$ at $N$. Then $BM 	imes DN = ?$

Accepted Answer

a constant

Answer

variable

Answer

zero

Answer

$AB \cdot CD$

In a parallelogram ABCDABCDABCD, a line through AAA meets BCBCBC at MMM and DCDCDC at NNN. Then BM×DN=?BM \times DN = ?BM×DN=?