The relation $\dfrac{AB}{AP} = \dfrac{AC}{AQ}$ in the proof follows from —

Question

Accepted Answer

Theorem 28 (corollary 1)

Answer

Pythagoras' theorem

Answer

SAS congruence

Answer

parallelogram law

The relation ABAP=ACAQ\dfrac{AB}{AP} = \dfrac{AC}{AQ}APAB​=AQAC​ in the proof follows from —