C-14-Q048: In the proof of Theorem 31, $BA:AE = BD:DC$ follows from —

C-14-Q048: In the proof of Theorem 31, $BA:AE = BD:DC$ follows from — | প্রশ্ন করি

In the proof of Theorem 31, BA:AE=BD:DCBA:AE = BD:DCBA:AE=BD:DC follows from —