C-07-Q018: In $\triangle ACD$, since $\angle ADC = \angle ACD$, it follows that—

C-07-Q018: In $\triangle ACD$, since $\angle ADC = \angle ACD$, it follows that— | প্রশ্ন করি

In △ACD\triangle ACD△ACD, since ∠ADC=∠ACD\angle ADC = \angle ACD∠ADC=∠ACD, it follows that—