The area of an isosceles triangle with equal sides $a$ and base $b$ is —

Question

Accepted Answer

$\dfrac{b}{4}\sqrt{4a^2 - b^2}$

Answer

$\dfrac{b}{2}\sqrt{4a^2 - b^2}$

Answer

$\dfrac{a}{4}\sqrt{4a^2 - b^2}$

Answer

$\dfrac{b}{4}\sqrt{a^2 - b^2}$

The area of an isosceles triangle with equal sides aaa and base bbb is —