The area of a triangle with sides $25, 27, 32$ cm (semi-perimeter $42$) equals —

Question

Accepted Answer

$\sqrt{42\cdot 17\cdot 15\cdot 10}$ sq cm

Answer

$\sqrt{42\cdot 25\cdot 27\cdot 32}$ sq cm

Answer

$42\cdot 17\cdot 15\cdot 10$ sq cm

Answer

$\dfrac{1}{2}\cdot 25\cdot 27$ sq cm

The area of a triangle with sides 25,27,3225, 27, 3225,27,32 cm (semi-perimeter 424242) equals —