C-13-Q076mediumsingle_mcqThe sum of the squares of the first nnn natural odd numbers is —an(2n−1)(2n+1)3\dfrac{n(2n - 1)(2n + 1)}{3}3n(2n−1)(2n+1)bn(n+1)(2n+1)6\dfrac{n(n + 1)(2n + 1)}{6}6n(n+1)(2n+1)cn2(n+1)24\dfrac{n^{2}(n + 1)^{2}}{4}4n2(n+1)2dn(n+1)n(n + 1)n(n+1)