$1^{3} + 2^{3} + 3^{3} + \cdots + n^{3} = ?$

Question

Accepted Answer

$\left[\dfrac{n(n+1)}{2}\right]^{2}$

Answer

$\dfrac{n(n+1)(2n+1)}{6}$

Answer

$\dfrac{n^{2}(n+1)}{2}$

Answer

$\dfrac{n^{2}(n-1)^{2}}{4}$

13+23+33+⋯+n3=?1^{3} + 2^{3} + 3^{3} + \cdots + n^{3} = ?13+23+33+⋯+n3=?