From $\left(\dfrac{x + a}{x - a}\right)^2 - 5\left(\dfrac{x + a}{x - a}\right) + 6 = 0$, with $y = \dfrac{x + a}{x - a}$

Question

From $\left(\dfrac{x + a}{x - a}\right)^2 - 5\left(\dfrac{x + a}{x - a}\right) + 6 = 0$, with $y = \dfrac{x + a}{x - a}$, the values of $y$ are—

Accepted Answer

$2, 3$

Answer

$1, 6$

Answer

$-2, -3$

Answer

$0, 5$

From (x+ax−a)2−5(x+ax−a)+6=0\left(\dfrac{x + a}{x - a}\right)^2 - 5\left(\dfrac{x + a}{x - a}\right) + 6 = 0(x−ax+a​)2−5(x−ax+a​)+6=0, with y=x+ax−ay = \dfrac{x + a}{x - a}y=x−ax+a​, the values of yyy are—