With standing piece $x$ and slanting piece $CD$ touching ground at $D$ where $BD=12$ m and $\angle BCD=30^\circ$, $ an

Question

With standing piece $x$ and slanting piece $CD$ touching ground at $D$ where $BD=12$ m and $\angle BCD=30^\circ$, $	an 30^\circ = \dfrac{12}{x}$ gives $x = ?$

Accepted Answer

$\dfrac{12}{	an 30^\circ}$

Answer

$12 \cdot 	an 30^\circ$

Answer

$12 \cdot \sin 30^\circ$

Answer

$\dfrac{12}{\sin 30^\circ}$

With standing piece xxx and slanting piece CDCDCD touching ground at DDD where BD=12BD=12BD=12 m and ∠BCD=30∘\angle BCD=30^\circ∠BCD=30∘, tan⁡30∘=12x\tan 30^\circ = \dfrac{12}{x}tan30∘=x12​ gives x=?x = ?x=?

With standing piece $x$ and slanting piece $CD$ touching ground at $D$ where $BD=12$ m and $\angle BCD=30^\circ$ , $\tan 30^\circ = \dfrac{12}{x}$ gives $x = ?$