C-08-Q163mediumsingle_mcqIn 0<θ<π20 < \theta < \dfrac{\pi}{2}0<θ<2π, the equation 2sin2θ−3cosθ=02\sin^{2}\theta - 3\cos\theta = 02sin2θ−3cosθ=0 yields cosθ\cos\thetacosθ equal to —a12\dfrac{1}{2}21b13\dfrac{1}{3}