C-08-Q161mediumsingle_mcqIn 0<θ<2π0 < \theta < 2\pi0<θ<2π, the solutions of sin2θ−cos2θ=cosθ\sin^{2}\theta - \cos^{2}\theta = \cos\thetasin2θ−cos2θ=cosθ are —aπ3, π, 5π3\dfrac{\pi}{3},\ \pi,\ \dfrac{5\pi}{3}3π, π, 3