In the $n\cdot\dfrac{\pi}{2}\pm heta$ method, when $n$ is even, the ratio —

Question

In the $n\cdot\dfrac{\pi}{2}\pm	heta$ method, when $n$ is even, the ratio —

Accepted Answer

remains the same

Answer

changes (sin to cos, etc.)

Answer

becomes zero

Answer

becomes undefined

In the n⋅π2±θn\cdot\dfrac{\pi}{2}\pm\thetan⋅2π​±θ method, when nnn is even, the ratio —