C-01-Q054mediumsingle_mcqDistributive law: A∪(B∩C)A \cup (B \cap C)A∪(B∩C) = ?a(A∩B)∪(A∩C)(A \cap B) \cup (A \cap C)(A∩B)∪(A∩C)b(A∪B)∩(A∪C)(A \cup B) \cap (A \cup C)