In $ riangle ABC$ with $\angle C$ acute, $BC = a$, $AC = b$, $CD$ is the orthogonal projection of $AC$ on $BC$, and $CE

Question

In $	riangle ABC$ with $\angle C$ acute, $BC = a$, $AC = b$, $CD$ is the orthogonal projection of $AC$ on $BC$, and $CE$ is the orthogonal projection of $BC$ on $AC$. Then —

Accepted Answer

$a \cdot CD = b \cdot CE$

Answer

$a \cdot CE = b \cdot CD$

Answer

$a \cdot b = CD \cdot CE$

Answer

$a + b = CD + CE$

In △ABC\triangle ABC△ABC with ∠C\angle C∠C acute, BC=aBC = aBC=a, AC=bAC = bAC=b, CDCDCD is the orthogonal projection of ACACAC on BCBCBC, and CECECE is the orthogonal projection of BCBCBC on ACACAC. Then —

In $\triangle ABC$ with $\angle C$ acute, $BC = a$ , $AC = b$ , $CD$ is the orthogonal projection of $AC$ on $BC$ , and $CE$ is the orthogonal projection of $BC$ on $AC$ . Then —