A semicircle is drawn on diameter $AB$. Two of its chords $AC$ and $BD$ intersect at point $P$. Then $AB^2 =$

Question

Accepted Answer

$AC \cdot AP + BD \cdot BP$

Answer

$AC \cdot BP + BD \cdot AP$

Answer

$AC \cdot BD + AP \cdot BP$

Answer

$AC^2 + BD^2$

A semicircle is drawn on diameter ABABAB. Two of its chords ACACAC and BDBDBD intersect at point PPP. Then AB2=AB^2 =AB2=