C-03-Q069mediumsingle_mcqIn △PQR\triangle PQR△PQR with ∠PQR=90°\angle PQR = 90°∠PQR=90° and EEE the midpoint of QRQRQR, then PR2=PR^2 =PR2=aPE2+QE2PE^2 + QE^2PE2+QE2bPE2+QE2+2RE2PE^2 + QE^2 + 2 RE^2