C-03-Q035mediumsingle_mcq

In $\triangle ABC$ , $\angle B = 60°$ . Then $AC^2 =$

A B^{2} + B C^{2} - A B \cdot B C

c

AB^2 + BC^2 + AB \cdot BC

d

AB^2 + BC^2 - 2 AB \cdot BC

In △ABC\triangle ABC△ABC, ∠B=60°\angle B = 60°∠B=60°. Then AC2=AC^2 =AC2=