Given $2^{2x} \cdot 2^{y-1} = 64$ and $6^x \cdot 3^{(y-2)/3} = 72$. Linearising the first equation gives:

Question

Accepted Answer

$2x + y - 1 = 6$

Answer

$2x + y = 7$

Answer

$2x - y = 1$

Answer

$x + 2y = 5$

Given 22x⋅2y−1=642^{2x} \cdot 2^{y-1} = 6422x⋅2y−1=64 and 6x⋅3(y−2)/3=726^x \cdot 3^{(y-2)/3} = 726x⋅3(y−2)/3=72. Linearising the first equation gives: