C-05-Q112mediumsingle_mcqIf a2x−1=a2p−1 (a>0, a≠1)a^{2x-1} = a^{2p-1}\ (a > 0,\ a \neq 1)a2x−1=a2p−1 (a>0, a=1), then x=x =x= —ap2\dfrac{p}{2}2pbpppc