Given $\sqrt{m-4} + \sqrt{m-10} = 6$ and $x^2 + 4x = m$, the values of $x$ are —

Question

Accepted Answer

$-\dfrac{13}{2},\ \dfrac{5}{2}$

Answer

$\dfrac{13}{2},\ -\dfrac{5}{2}$

Answer

$-5,\ 2$

Answer

$5,\ -2$

Given m−4+m−10=6\sqrt{m-4} + \sqrt{m-10} = 6m−4​+m−10​=6 and x2+4x=mx^2 + 4x = mx2+4x=m, the values of xxx are —