One solution of $x^2 - 2xy + 8y^2 = 8,\ 3xy - 2y^2 = 4$ is —

Question

Accepted Answer

$\left(3,\ \dfrac{1}{2}\right)$

Answer

$(3, 2)$

Answer

$(1, 3)$

Answer

$\left(-3,\ \dfrac{1}{2}\right)$

One solution of x2−2xy+8y2=8, 3xy−2y2=4x^2 - 2xy + 8y^2 = 8,\ 3xy - 2y^2 = 4x2−2xy+8y2=8, 3xy−2y2=4 is —