After substituting $p = a^x$, the equation $a^{2x} - (a^2+1)a^x + a^2 = 0$ becomes —

Question

Accepted Answer

$p^2 - (a^2+1)p + a^2 = 0$

Answer

$p^2 + (a^2+1)p - a^2 = 0$

Answer

$p^2 - a^2p + 1 = 0$

Answer

$p - (a^2+1) + a^2 = 0$

After substituting p=axp = a^xp=ax, the equation a2x−(a2+1)ax+a2=0a^{2x} - (a^2+1)a^x + a^2 = 0a2x−(a2+1)ax+a2=0 becomes —