C-05-Q038mediumsingle_mcqTo solve x2−6x+15−x2−6x+13=10−8\sqrt{x^2-6x+15} - \sqrt{x^2-6x+13} = \sqrt{10} - \sqrt{8}x2−6x+15−x2−6x+13=10−8, the most useful substitution is —ay=x2−6x+13y = x^2 - 6x + 13y=x2−6x+13by=x