The two roots of $ax^2 + bx + c = 0$ are given by —

Question

Accepted Answer

$x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Answer

$x = \dfrac{-b \pm \sqrt{b^2 + 4ac}}{2a}$

Answer

$x = \dfrac{b \pm \sqrt{b^2 - 4ac}}{2a}$

Answer

$x = \dfrac{-b \pm \sqrt{4ac - b^2}}{2a}$

The two roots of ax2+bx+c=0ax^2 + bx + c = 0ax2+bx+c=0 are given by —