C-11-Q095mediumsingle_mcqThe equation of the straight line through (−2,−3)(-2, -3)(−2,−3) with slope 3 is —ay=3x+3y = 3x + 3y=3x+3by=3x−3y = 3x - 3y=3x−3cy=3x+9y = 3x + 9y=3x+9dy=−3x+3y = -3x + 3y=−3x+3