Resolving $\dfrac{x + 5}{(x-1)(x-2)(x-3)}$ as $\dfrac{A}{x-1} + \dfrac{B}{x-2} + \dfrac{C}{x-3}$, the constants are:

Question

Accepted Answer

$A = 3, B = -7, C = 4$

Answer

$A = 4, B = -3, C = 7$

Answer

$A = -3, B = 7, C = 4$

Answer

$A = 3, B = 7, C = -4$

Resolving x+5(x−1)(x−2)(x−3)\dfrac{x + 5}{(x-1)(x-2)(x-3)}(x−1)(x−2)(x−3)x+5​ as Ax−1+Bx−2+Cx−3\dfrac{A}{x-1} + \dfrac{B}{x-2} + \dfrac{C}{x-3}x−1A​+x−2, the constants are: