C-04-Q087mediumsingle_mcqThe reaction Na(1s22s22p63s1)→Na+(1s22s22p6)+e−\text{Na}(1s^2 2s^2 2p^6 3s^1)\rightarrow \text{Na}^+(1s^2 2s^2 2p^6) + e^-Na(1s22s22p63s1)→Na+(1s22s22p6)+e− shows that Na—aaccepts an electronbloses an electron and becomes a cationcshares an electron pairdis an inert gas