C-06-Q197: In $\mathrm{2Mg + O_2 \to 2MgO}$, $\mathrm{O_2}$ needed for 24 g Mg—

C-06-Q197: In $\mathrm{2Mg + O_2 \to 2MgO}$, $\mathrm{O_2}$ needed for 24 g Mg— | প্রশ্ন করি

In 2Mg+O2→2MgO\mathrm{2Mg + O_2 \to 2MgO}2Mg+O2​→2MgO, O2\mathrm{O_2}O2​ needed for 24 g Mg—